LeetCode 3761 - Minimum Absolute Distance Between Mirror Pairs

LeetCode Problem 3761

Difficulty: 🟡 Medium
Topics: Array, Hash Table, Math

Solution

Correctness

The proposed solution does not answer the question that Exercise 4.3.1.17 asks. The exercise is specific: given that $v_{n-1} \ge \lfloor b/2 \rfloor$ and $u_n = v_{n-1}$, one must show that the quotient digit $q$ in the division step satisfies $q = b-1$ or $q = b-2$. This is a statement about bounds on the first quotient digit in division, not about subtraction, Algorithm S, or complement correction. The solution provided instead repeats a general discussion about Algorithm S, final borrows, and radix-$b$ complements. It does not address the relationship between $u_n, v_{n-1}, b$ and the possible values of $q$.

Gaps and Errors

1. Critical error - completely off-topic: The entire solution discusses subtraction, final borrow, and radix-$b$ complement correction, none of which is relevant to showing that $q = b-1$ or $b-2$ in the division algorithm context. This is a fundamental misinterpretation of the exercise.
2. No connection to exercise assumptions: There is no use of $v_{n-1} \ge \lfloor b/2 \rfloor$ or the condition $u_n = v_{n-1}$. The key reasoning needed - comparing the first few digits of the dividend and divisor to bound the quotient digit - is entirely absent.
3. No proof of the claimed result: The exercise requires a precise proof that $q$ must be $b-1$ or $b-2$, based on the digit-level inequalities, which is completely missing.
4. Justification gaps are irrelevant here because the main argument itself is off-target.

Summary

The solution does not attempt the actual exercise. It is a complete misinterpretation and therefore cannot be considered correct or complete.

VERDICT: FAIL - the solution addresses Algorithm S and complements instead of proving the bound on the first quotient digit $q$.